问题
解答题
解答下列问题 (1)已知a=
(2)已知x=2-
(3)己知x=
|
答案
(1)a2+ab+b2,
=a2+2ab+b2-ab,
=(a+b)2-ab,
当a=
+1,b=2
-1时,2
原式=(
+1+2
-1)2-(2
+1)(2
-1),2
=2-1,
=1;
(2)x2-xy+y2,
=x2-2xy+y2-xy,
=(x-y)2-xy
当x=2-
,y=2+3
时,3
原式=(2+
-2+3
)2-(2-3
)(2+3
),3
=16-1,
=15;
(3)
÷(2+x-x x-2
),4 2-x
=
÷x x-2
,-x2 2-x
=
×x x-2
,x-2 x2
=1 x
当x=
-1时,原式=2
,1
-12
=
+1.2