问题
解答题
若a=1-
|
答案
+a2-1 a2+a a2-2a+1 a2-a
=
+(a+1)(a-1) a(a+1)
.(a-1)2 a(a-1)
∵a=1-
<1,2
∴原式=
+a-1 a
=-1 a
.a-2 a
把a=1-
代入得:2
=a-2 a
=1-
-22 1- 2
=(1+-1- 2 1- 2
)2=3+22
.2
若a=1-
|
+a2-1 a2+a a2-2a+1 a2-a
=
+(a+1)(a-1) a(a+1)
.(a-1)2 a(a-1)
∵a=1-
<1,2
∴原式=
+a-1 a
=-1 a
.a-2 a
把a=1-
代入得:2
=a-2 a
=1-
-22 1- 2
=(1+-1- 2 1- 2
)2=3+22
.2