问题
解答题
已知a=2-
|
答案
∵a=2-
,3
∴a-1=1-3
∴
-a2-1 a+1
-a2-2a+1 a2-a 1 a
=
-(a+1)(a-1) a+1
-|a-1| a(a-1) 1 a
=a-1-
--(a-1) a(a-1) 1 a
=a-1+
-1 a 1 a
=a-1
=1-
.3
已知a=2-
|
∵a=2-
,3
∴a-1=1-3
∴
-a2-1 a+1
-a2-2a+1 a2-a 1 a
=
-(a+1)(a-1) a+1
-|a-1| a(a-1) 1 a
=a-1-
--(a-1) a(a-1) 1 a
=a-1+
-1 a 1 a
=a-1
=1-
.3