问题
解答题
已知x=2-
|
答案
∵x=2-
<1,3
∴
-1-2x+x2 x-1 x2-2x+1 x-1
=
-(1-x)2 x-1 (x-1)2 x-1
=x-1-
=x,1-x x-1
当x=2-
时,原式=2-3
.3
已知x=2-
|
∵x=2-
<1,3
∴
-1-2x+x2 x-1 x2-2x+1 x-1
=
-(1-x)2 x-1 (x-1)2 x-1
=x-1-
=x,1-x x-1
当x=2-
时,原式=2-3
.3