问题 解答题
若x=
3
-1
3
+1
,y=
3
+1
3
-1
,求
x2+y2+2
的值.
答案

因为x=

3
-1
3
+1
,y=
3
+1
3
-1

所以x+y=

3
-1
3
+1
+
3
+1
3
-1

=

(
3
-1)
2
+(
3
+1)
2
(
3
+1)(
3
-1)

=

4-2
3
+4+2
3
(
3
)
2
-1

=4.

x•y=

3
-1
3
+1
3
+1
3
-1
=1

所以,

x2+y2+2

=

(x+y)2-2xy+2

=

42-2×1+2

=4.

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