问题
解答题
已知x1=
|
答案
x1•x2=
×-b+ b2-4ac 2a -b- b2-4ac 2a
=(-b+
)(-b-b2-4ac
)b2-4ac 4a2
=b2-(b2-4ac) 4a2
=4ac 4a2
=
.c a
已知x1=
|
x1•x2=
×-b+ b2-4ac 2a -b- b2-4ac 2a
=(-b+
)(-b-b2-4ac
)b2-4ac 4a2
=b2-(b2-4ac) 4a2
=4ac 4a2
=
.c a