问题
解答题
计算
|
答案
∵
=1 (n+1)
+nn n+1 (n+1)
-nn n+1 (n+1)2n-n2(n+1)
=(n+1)
-nn n+1 n(n+1)
=
-1 n
,1 n+1
∴原式=1-
+1 2
-1 2
+1 3
-1 3
+…+1 4
-1 2003 1 2004
=1-
.1 2004
计算
|
∵
=1 (n+1)
+nn n+1 (n+1)
-nn n+1 (n+1)2n-n2(n+1)
=(n+1)
-nn n+1 n(n+1)
=
-1 n
,1 n+1
∴原式=1-
+1 2
-1 2
+1 3
-1 3
+…+1 4
-1 2003 1 2004
=1-
.1 2004