问题
选择题
已知△ABC为等边三角形,AB=2.设点P,Q满足
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答案
∵
=λAP
,AB
=(1-λ)AQ
,λ∈RAC
∴
=BQ
+BA
=AQ
+(1-λ)BA
,AC
=CP
+CA
=AP
+λCA AB
∵△ABC为等边三角形,AB=2
∴
•BQ
=CP
•BA
+λCA
•BA
+(1-λ)AB
•AC
+λ(1-λ)CA
•AC AB
=2×2×cos60°+λ×2×2×cos180°+(1-λ)×2×2×cos180°+λ(1-λ)×2×2×cos60°
=2-4λ+4λ-4+2λ-2λ2,
=-2λ2+2λ-2
∵
•BQ
=-CP 3 2
∴4λ2-4λ+1=0
∴(2λ-1)2=0
∴λ=1 2
故选A