问题 解答题
(1)先化简,再求值:(
3a
a+1
-
a2-1
a+1
)•
a2-1
a
,其中a=
7
+1(精确到0.01);
(2)当b≠0时,比较
b+1
与1的大小.
答案

(1)原式=

3a
a+1
(a-1)(a+1)
a
-
(a-1)(a+1)
a+1
(a-1)(a+1)
a
=3(a-1)-
(a+1)(a-1)2
a

当a=

7
+1时,

原式=3(

7
+1)-
(
7
+1+1)(
7
+1-1)
2
7
+1

=3

7
+3-
7(
7
+2)
7
+1

=3

7
+3-
7(
7
+2)(
7
-1)
6

=3

7
+3-
7(5+
7
)
6

=3

7
+3-
35
6
-
7
7
6

=

11
7
6
-
17
6

=

11
7
-17
6

11×2.646-17
6

=2.02;

(2)因为b+1<0时二次根式无意义,所以:

①0<b+1<1时,

b+1
<1;

②b+1=1时,

b+1
=1;

③b+1>1时,

b+1
>1.

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