问题 问答题

【说明】本程序实现功能:读入两个整数,第1个数除以第2个数,声明当除数为零时抛出异常类DivideByZeroException。
public class DivideByZeroException (1)
public DivideByZeroException ( )
super("Attcmpted to divide by zero");


import java.io. *;
public class Example
private static int quotient(int numerator, in)\”t denominator) throws
DivideByZeroException
if (denominator==0)
throw (2) ;
return(numerator / denominator);

public static void main(String args[])
int number1=0, number2=0, result0;
try
System.out.print1n("Enter the first number:");
number1 = Integer. valueOf(Keyboard.getString()).intValue();
System.out.print1n("Enter the second number:");
number2 = Integer. Va1ueOf(Keyboard.getString()).intValue();
result = quotient(number1,number2);

catch (NumberFormatException e)
System.out.print1n("Invalid integer entered!");
System. exit(-1);

catch ( (3) )
System.out.print1n(e.to String());
System.exit(-1);

Systcm.out.pfint1n(number1 + "/" + number2 + "=" + result);
其中, Keyboard类的声明为:
import java.io.*;
public class Keyboard
static BufferedReader inputStream = (4)
(new InputStreamReader(System.in));
public static int getInteger()
try(
return (Intoger.valueOf(inputStream.readLine().trim()).intValue());
catch (Exception e)
e.printStackTrace();
return 0;


public static String getString()
try
return (inputStream.readLine());
catch ( (5) )
return "0";

答案

参考答案:
(1)extends ArithmeticException
DivideByZeroException类从ArithmeticException类扩展而来。
(2)new DivideByZeroExeeption()
throw一个DivideByZeroException异常函数,打印错误信息。
(3)DivideByZeroException e
捕捉DivideByZeroExeeption异常信息。
(4)new BufferedReader
动态生成一个BufferedReader对象用于输入。
(5)IOException e
字符串成员函数getString中捕捉输入输出异常信息。

单项选择题
单项选择题