问题
选择题
已知
|
答案
由题意可得|
|=|e1
|=1,e2
2+e1
2+2e2
•e1
≤1,∴e2
•e1
≤-e2
.1 2
∵(
+OP
)2=OQ
2+OP
2+2 OQ
•OP
=m2+n2+2mnOQ
•e1
≤m2+n2-mn,e2
故选A.
已知
|
由题意可得|
|=|e1
|=1,e2
2+e1
2+2e2
•e1
≤1,∴e2
•e1
≤-e2
.1 2
∵(
+OP
)2=OQ
2+OP
2+2 OQ
•OP
=m2+n2+2mnOQ
•e1
≤m2+n2-mn,e2
故选A.