问题 解答题
(1)
1
3
x2y
×(-6
y2
x
) (x>0,y>0);
(2)(1-2
3
)(1+2
3
)-(2
3
+1)2
答案

(1)原式=

1
3
×(-6)
x2
y2
x

=-2

xy3

=-2y

xy

(2)原式=1-(2

3
2-[(2
3
2+4
3
+1]

=1-12-12-4

3
-1

=-24-4

3

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