问题
解答题
(1)
(2)(1-2
|
答案
(1)原式=
×(-6)1 3 x2y× y2 x
=-2xy3
=-2y
;xy
(2)原式=1-(2
)2-[(23
)2+43
+1]3
=1-12-12-4
-13
=-24-4
.3
(1)
(2)(1-2
|
(1)原式=
×(-6)1 3 x2y× y2 x
=-2xy3
=-2y
;xy
(2)原式=1-(2
)2-[(23
)2+43
+1]3
=1-12-12-4
-13
=-24-4
.3