问题
填空题
函数y=(sinx-
|
答案
∵y=(sinx-
cosx)(cosx-3
sinx) +3 3
=sinxcosx-
sin2x-3
cos2x +3sinxcosx+3 3
=4sinxcosx
=2sin2x
∴T=
=π2π 2
故答案为：π．
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函数y=(sinx-
|
∵y=(sinx-
cosx)(cosx-3
sinx) +3 3
=sinxcosx-
sin2x-3
cos2x +3sinxcosx+3 3
=4sinxcosx
=2sin2x
∴T=
=π2π 2
故答案为：π．