问题
解答题
设向量
(1)求
(2)求
|
答案
(1)∵
•a
=cos23°cos68°+cos67°cos22°b
=sin67°cos68°+cos67°sin68°
=sin(67°+68°)
=sin135°=
…5分2 2
(2)∵
=u
+ta
=(cos23°+tcos68°,cos67°+tcos22°),b
∴|
|2=(cos23°+tcos68°)2+(cos67°+tcos22°)2u
=(cos23°+tsin22°)2+(sin23°+tcos22°)2
=cos223°+sin223°+t2(sin222°+cos222°)+2t(cos23°sin22°+sin23°cos22°)
=1+t2+
t…10分2
=(t+
)2+2 2
≥1 2
…12分1 2
∴|
|≥u
.2 2
故
的模的最小值为u
,此时t=-2 2
…14分2 2