问题
解答题
(1)计算:
(2)解方程:(x-2)(x+5)=6. |
答案
(1)原式=2-
+22
=2+2
;2
(2)(x-2)(x+5)=6,
去括号得:x2+5x-2x-10=6,即x2+3x-16=0,
这里a=1,b=3,c=-16,
∵△=b2-4ac=9+64=73,
∴x=
,-3± 73 2
则x1=
,x2=-3+ 73 2
.-3- 73 2
(1)计算:
(2)解方程:(x-2)(x+5)=6. |
(1)原式=2-
+22
=2+2
;2
(2)(x-2)(x+5)=6,
去括号得:x2+5x-2x-10=6,即x2+3x-16=0,
这里a=1,b=3,c=-16,
∵△=b2-4ac=9+64=73,
∴x=
,-3± 73 2
则x1=
,x2=-3+ 73 2
.-3- 73 2