问题
填空题
△ABC外接圆的半径为1,圆心为O,且2
|
答案
∵2
+OA
+AB
=AC
,∴0
+OA
+AB OA
=+AC
,∴0
=-OB
.OC
∴O,B,C共线,BC为圆的直径,∴AB⊥AC.
∵|
|=|OA
|,∴|AB
|=|OA
|=1,|BC|=2,|AC|=AB
,故∠ACB=3
.π 6
则
•CA
=CB
×2cos3
=3,π 6
故答案为:3.