问题
解答题
已知
(1)当
(2)若
|
答案
(1)∵
∥a
,∴sinθcosθ=b
.2 5
∴(sinθ-cosθ)2=1-2sinθcosθ=1-2×
=2 5
,1 5
∵θ∈(
,π 4
),∴sinθ>cosθ,π 2
∴cosθ-sinθ=-
.5 5
(2)∵
⊥a
,∴b
cosθ+2sinθ=0.1 5
∴cosθ=-10sinθ.
∴
+1+sinθ 1-sinθ
=1-sinθ 1+sinθ
=(1+sinθ)2+(1-sinθ)2 1-sin2θ
=2+2sin2θ cos2θ 2(sin2θ+cos2θ)+2sin2θ cos2θ
=
=4sin2θ+2cos2θ cos2θ
=4sin2θ+2×100sin2θ 100sin2θ
.51 25