问题
填空题
已知Rt△ABC的斜边BC=5,则
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答案
设AC=b,AB=c,
原式=5bcos(180°-C)+0+5ccos(180°-B)
=-5bcosC-5ccosB
=-5(asinA+csinC)
=-5(2Rsin2A+2Rsin2B)
=-5×2R,
∵R是三角形外接圆的半径,
∴2R=5,
∴原式=-25,
故答案为:-25.
已知Rt△ABC的斜边BC=5,则
|
设AC=b,AB=c,
原式=5bcos(180°-C)+0+5ccos(180°-B)
=-5bcosC-5ccosB
=-5(asinA+csinC)
=-5(2Rsin2A+2Rsin2B)
=-5×2R,
∵R是三角形外接圆的半径,
∴2R=5,
∴原式=-25,
故答案为:-25.
阅读理解。 | |||||
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