问题
解答题
计算: (1)(5-
(2)
(3)(
(4)
|
答案
(1)原式=25-10
+77
=32-10
;7
(2)原式=2
+42
-2 2
=5
;2
(3)原式=[(
-2)(5
+2)]2003(5
-2)5
=(5-4)2003(
-2)5
=
-2;5
(4)原式=
+14
+3 3 3
=
+15 3 3
=5+1
=6.
计算: (1)(5-
(2)
(3)(
(4)
|
(1)原式=25-10
+77
=32-10
;7
(2)原式=2
+42
-2 2
=5
;2
(3)原式=[(
-2)(5
+2)]2003(5
-2)5
=(5-4)2003(
-2)5
=
-2;5
(4)原式=
+14
+3 3 3
=
+15 3 3
=5+1
=6.