问题 解答题
计算:
(1)(5-
7
2
(2)
8
+
32
-
2

(3)(
5
-2)2004×(
5
+2)2003
(4)
2
12
+
3
3
+(1-
3
0
答案

(1)原式=25-10

7
+7

=32-10

7

(2)原式=2

2
+4
2
-
2

=5

2

(3)原式=[(

5
-2)(
5
+2)]2003
5
-2)

=(5-4)2003

5
-2)

=

5
-2;

(4)原式=

4
3
+
3
3
+1

=

5
3
3
+1

=5+1

=6.

多项选择题
单项选择题