问题 问答题

将A物质25g、B物质5g混合加热,反应后的物质中A仍有10g,B已反应完,同时生成C物质11g,还有一种生成物D,则这个化学反应中,参加反应的各物质与生成的各物质间的质量比为A:B:C:D=______.如果A、B、C、D相对分子质量分别为30、20、

44、18,则在化学方程式中A、B、C、D四种物质的系数分别为______.反应方程式为______.

答案

由题意可知,(25g-10g)A和5克B反应能生成11克C,生成D的质量为:15克+5克-11克=9克,则A、B、C、D四种物质的质量比为:15:5:11:9;

设ABCD四种物质化学式之前的化学计量数分别是abcd,则有aA:bB:cC:dD=15:5:11:9,因A、B、C、D相对分子质量分别为30、20、44、18,

故30a:20b:44c:18d=15:5:11:9,则abcd的数值比是2:1:1:2,则该反应的化学方程式为:2A+B=C+2D

故答案为:15:5:11:9;2:1:1:2;2A+B=C+2D.

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