问题
填空题
正三角形ABC边长为2,设
|
答案
由题意可得
=AD
(1 2
+AB
),AC
=BE 1 3
-AC
,AB
2 = AB
2 =4,AC
•AC
=2×2×cos60°=2.AB
∴
•AD
=BE
(1 2
+AB
)•(AC 1 3
-AC
)=AB
•1 6
•AB
-AC 1 2
2+AB 1 6
2-AC 1 2
•AC
=-AB 1 3
•AC
-AB
×4+1 2
×4=-2,1 6
故答案为-2.