问题
选择题
已知i是虚数单位,(1+2i)z1=-1+3i,z2=1+(1+i)10,z1、z2在复平面上对应的点分别为A、B,O为坐标原点,则
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答案
∵(1+2i)z1=-1+3i,∴z=
=-1+3i 1+2i
=(-1+3i)(1-2i) (1+2i)(1-2i)
=1+i,∴5+5i 5
=(1,1)OA
∵z2=1+(1+i)10=1+(2i)5=1+32i,∴
=(1,32)OB
则
•OA
=(1,1)•(1,32)=33OB
故选A