问题 解答题
计算:
(1)2(1+
2
)+
48
+4
1
2

(2)9
3x
-7
12x
+2
6
×3
8x

(3)(7+4
3
)(2-
3
)2+(2+
3
)(2-
3
)

(4)-22×
8
+3
2
(3-2
2
)-
1
1+
2

(5)
2x
3
9x
-x2
1
x3
+6x
x
16

(6)2a[
3ab2
-(
1
12
27ab2
-b
3a
4
)](b≥0).
答案

(1)原式=2+2

2
+4
3
+2
2

=2+4

2
+4
3

(2)原式=9

3x
-14
3x
+24
3x

=19

3x

(3)原式=(7+4

3
)(7-4
3
)+4-3

=49-48+1

=2;

(4)原式=-4×

2
+9
2
-12-(
2
-1

=-8

2
+9
2
-12-
2
+1

=-11;

(5)原式=

2x
3
 ×3 
x
-x2 × 
1
 x 
x
+6x× 
x
4

=2x

x
x
+
3
2
x
x

=

7x-2
2
x

(6)原式=2a(b

3a
-
1
12
×3b 
3a
+
3a
2

=2ab

3a
-
ab 
3a
2
+ab
3a

=

5
2
ab
3a

材料分析题
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