问题
填空题
若向量
|
答案
∵|
|=1,|a
|=2,<b
,a
>=b
,π 3
∴
•a
=|b
| |a
|cosb
=1×2×π 3
=1.1 2
|
+a
|=b
=
2+2a
•a
+b
2b
=12+2×1+22
.7
故答案为1,
.7
若向量
|
∵|
|=1,|a
|=2,<b
,a
>=b
,π 3
∴
•a
=|b
| |a
|cosb
=1×2×π 3
=1.1 2
|
+a
|=b
=
2+2a
•a
+b
2b
=12+2×1+22
.7
故答案为1,
.7