问题
解答题
计算:(1)(
(2)
|
答案
(1)原式=(4
-33
)(42
+33
)-(2
-3
)22
=(4
)2-(33
)2-(3-22
+2)6
=48-18-5+26
=25+2
;6
(2)原式=2b
×(-ab
a3 2
)×ab a 3 ab
=-a2b
.ab
计算:(1)(
(2)
|
(1)原式=(4
-33
)(42
+33
)-(2
-3
)22
=(4
)2-(33
)2-(3-22
+2)6
=48-18-5+26
=25+2
;6
(2)原式=2b
×(-ab
a3 2
)×ab a 3 ab
=-a2b
.ab