问题
解答题
(1)计算:
(2)解方程:x2+3x-1=0. |
答案
(1)原式=
-48÷3
+2
×121 2
=4+6
;6
(2)这里a=1,b=3,c=-1,
∵△=9+4=13,
∴x=
,-3± 13 2
则x1=
,x2=-3+ 13 2
.-3- 13 2
(1)计算:
(2)解方程:x2+3x-1=0. |
(1)原式=
-48÷3
+2
×121 2
=4+6
;6
(2)这里a=1,b=3,c=-1,
∵△=9+4=13,
∴x=
,-3± 13 2
则x1=
,x2=-3+ 13 2
.-3- 13 2