问题 填空题
设点O是△ABC的外心,AB=13,AC=12,则
BC
AO
=______.
答案

过O作OS⊥AB,OT⊥AC垂足分别为S,T 则S,T分别是AB,AC的中点,

BC
AO
=(
BA
+
AC
)•
AO
=
BA
AO
+
AC
AO

=-|

BA
||
AS
|+|
AC
|•|
AT
|=-13×
13
2
+12×
12
2

=-

25
2

故答案为:-

25
2

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