问题
解答题
计算下列各题 (1)
(2)(2
|
答案
(1)原式=2b
×(-ab 3a 2
)÷3ab ab a
=-3ab×(
)2÷ab 3 ab a
=-a2b
.ab
(2)原式=(2
+33
+22
-33
)(22
+33
-22
+33
)2
=4
×63 2
=24
.6
计算下列各题 (1)
(2)(2
|
(1)原式=2b
×(-ab 3a 2
)÷3ab ab a
=-3ab×(
)2÷ab 3 ab a
=-a2b
.ab
(2)原式=(2
+33
+22
-33
)(22
+33
-22
+33
)2
=4
×63 2
=24
.6