问题
解答题
计算: (1)
(2)(
|
答案
(1)原式=-3 b
÷3a4b6 b a
=-
×3 b
×1 3 a4b6× a b
=-1 b a5b5
=-a2b
;ab
(2)原式=(6
+2
)•
(2-2
)3 (2+
)(2-3
)3
-73 6
=(6
+22
-2
)•6
-73 6
=6
+26
-36
-72 6
=
-36
.2
计算: (1)
(2)(
|
(1)原式=-3 b
÷3a4b6 b a
=-
×3 b
×1 3 a4b6× a b
=-1 b a5b5
=-a2b
;ab
(2)原式=(6
+2
)•
(2-2
)3 (2+
)(2-3
)3
-73 6
=(6
+22
-2
)•6
-73 6
=6
+26
-36
-72 6
=
-36
.2