问题 选择题 用加减法解方程组5x+y=4(1)7x+2y=-9(2)时,(1)×2-(2)得( )A.3x=-1B.-2x=13C.17x=-1D.3x=17 答案 (1)×2-(2),得2(5x+y)-(7x+2y)=2×4-(-9),去括号,得10x+2y-7x-2y=2×4+9,化简,得3x=17.故选D.