问题
填空题
已知tan(π+α)=
|
答案
tan(π+α)=
,所以tanα=1 2
,sin2α=1 2
=2sinαcosα sin2α+cos2α
=2tanα tan2α+1
=2× 1 2 (
)2+11 2
.4 5
故答案为:
.4 5
已知tan(π+α)=
|
tan(π+α)=
,所以tanα=1 2
,sin2α=1 2
=2sinαcosα sin2α+cos2α
=2tanα tan2α+1
=2× 1 2 (
)2+11 2
.4 5
故答案为:
.4 5