问题
单项选择题
多项式M=4x2-9x+4a,N=3x2-9x+4a,当x为任意一个有理数时,下列结论正确的是()。
A.M的值必小于N的值
B.M的值必不大于N的值
C.M的值必大于N的值
D.M的值必不小于N的值
答案
参考答案:D
解析:
M-N=(4x2-9x+4a)-(3x2-9x+4a)=x2≥0,故M>N或M=N,选D。
多项式M=4x2-9x+4a,N=3x2-9x+4a,当x为任意一个有理数时,下列结论正确的是()。
A.M的值必小于N的值
B.M的值必不大于N的值
C.M的值必大于N的值
D.M的值必不小于N的值
参考答案:D
解析:
M-N=(4x2-9x+4a)-(3x2-9x+4a)=x2≥0,故M>N或M=N,选D。
选词填空,并注意词形变化。 | |
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