问题
解答题
(1)
(2)(2
|
答案
(1)原式=
•196×102×10 4 102
=14×10×
×10
=282 10
;10
(2)原式=20+
•41 4
+2 2 2
-2
×51 5
=20+2
+2
-2
=20+2
.2
(1)
(2)(2
|
(1)原式=
•196×102×10 4 102
=14×10×
×10
=282 10
;10
(2)原式=20+
•41 4
+2 2 2
-2
×51 5
=20+2
+2
-2
=20+2
.2