问题
解答题
计算 (1)(
(2)
(3)
(4)(3
(5)(
|
答案
(1)原式=(4
+23
)-(25
-3
)5
=4
+23
-25
+3 5
=2
+33
.5
(2)原式=
÷15 3
×21 3
=35 5
×5 7
=1;35 5
(3)原式=
×(3a 2b
÷ab a
)=2 b b
×3a 2b
=b a 2a
;3 4
(4)原式=45-75=-30;
(5)原式=3
-5+18-65
=13-35
.5