问题 解答题
计算
(1)(
3
+
2
)
(
3
-
2
)

(2)
6
×
3
2
+(1-
5
)0

(3)
27
-
1
3
+
12

(4)(2-
10
)2+
40
答案

(1)原式=(

3
2-(
2
2

=3-2

=1;

(2)原式=

6×3
2
+1

=3+1

=4;

(3)原式=3

3
-
3
3
+2
3

=

14
3
3

(4)原式=4-4

10
+10+2
10

=14-2

10

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