问题 填空题
0<α<
π
2
,-
π
2
<β<0
cos(
π
4
+α)=
1
3
cos(
π
4
-
β
2
)=
3
3
,则cos(α+
β
2
)
=______.
答案

0<α<

π
2
,-
π
2
<β<0

π
4
π
4
+α<
4
π
4
π
4
-
β
2
π
2

cos(

π
4
+α)=
1
3
cos(
π
4
-
β
2
)=
3
3

sin(

π
4
+α)=
2
2
3
sin(
π
4
-
β
2
)=
6
3

cos(α+

β
2
)=cos[(
π
4
+α)-(
π
4
-
β
2
)]
=
1
3
×
3
3
+
2
2
3
×
6
3
=
5
3
9

故答案为:

5
3
9

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