问题
解答题
计算: (1)
(2)
(3)
(4)
|
答案
(1)原式=3
-23
+33 5
=
+33
;5
(2)原式=2
+3×2
-3 3
+2
×2 2 3 2
=2
+2
-3 1 2
+2 1 2 3
=3 2
+2 3 2
;3
(3)原式=
×22 2
+12
×42 2
-1 8
×32 2 48
=2
+1-66 6
=1-4
;6
(4)原式=(
•1•1 2b
)1 2 3a•
•b a b 1
=1 4b 3b2
=
.3 4