问题
解答题
计算: (1)(1+
(2)(
(3)(
|
答案
(1)原式=(1-3)×(1-2)=2;
(2)原式=[(
+3
)(2
-3
)]2=[(2
)2-(3
)2]2=(3-2)2=1;2
(3)原式=[(
-3
)+36
][(2
-3
)-36
]2
=(
-3
)2-(36
)22
=3-6
+6-182
=-9-6
.2
计算: (1)(1+
(2)(
(3)(
|
(1)原式=(1-3)×(1-2)=2;
(2)原式=[(
+3
)(2
-3
)]2=[(2
)2-(3
)2]2=(3-2)2=1;2
(3)原式=[(
-3
)+36
][(2
-3
)-36
]2
=(
-3
)2-(36
)22
=3-6
+6-182
=-9-6
.2