问题
解答题
计算: (1)
(2)(
(3)(2
(4)
(5)
(6)
(7)(π-2009)0+
|
答案
(1)原式=
=2
+33 3 3
=5;5 3 3
(2)原式=(
)2-(5
)2=5-3=2;3
(3)原式=(2
)2-42
×2
+(3
)2=8-43
+3=11-46
;6
(4)原式=2
-33
+53
=43
;3
(5)原式=3
-3
+23 3
=3
;14 3 3
(6)原式=3-
=3-2=1;
×2
×2 3 3
(7)原式=1+2
+2-3
=3+3
.3