问题
选择题
函数sinx=2cosx,则sinx•cosx的值是( )
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答案
∵sinx=2cosx,∴
=2,即tanx=2sinx cosx
∴sinx•cosx=
=sinx•cosx 1
=sinx•cosx sin2x+cos2x
=sinx•cosx cos2x
+sin2x cos2x cos2x cos2x
=tanx tan2x+1 2 5
故选C
函数sinx=2cosx,则sinx•cosx的值是( )
|
∵sinx=2cosx,∴
=2,即tanx=2sinx cosx
∴sinx•cosx=
=sinx•cosx 1
=sinx•cosx sin2x+cos2x
=sinx•cosx cos2x
+sin2x cos2x cos2x cos2x
=tanx tan2x+1 2 5
故选C