问题 解答题
计算:
(1)
20
+
125
5
-5
           (2)(3
3
-2
2
)2

(3)(3
2
+2
3
)(
6
-3)
答案

(1)原式=

2
5
+5
5
5
-5

=7-5

=2;

(2)原式=(3

3
2-2×3
3
×2
2
+(2
2
2

=27-12

6
+8

=35-12

6

(3)原式=3

2
×
6
-3
2
×3+2
3
×
6
-2
3
×3

=6

3
-9
2
+6
2
-6
3

=-3

2

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