问题
解答题
计算: (1)
(3)(3
|
答案
(1)原式=
-52
+55 5 5
=7-5
=2;
(2)原式=(3
)2-2×33
×23
+(22
)22
=27-12
+86
=35-12
;6
(3)原式=3
×2
-36
×3+22
×3
-26
×33
=6
-93
+62
-62 3
=-3
.2
计算: (1)
(3)(3
|
(1)原式=
-52
+55 5 5
=7-5
=2;
(2)原式=(3
)2-2×33
×23
+(22
)22
=27-12
+86
=35-12
;6
(3)原式=3
×2
-36
×3+22
×3
-26
×33
=6
-93
+62
-62 3
=-3
.2