问题
填空题
已知tanx=2,则
|
答案
∵tanx=2,
则
3sin2x+2cos2x |
cos2x-3sin2x |
6sinxcosx+2(cos2x-sin2x) |
cos2x-sin2x-6sinxcosx |
=
| ||||
|
=
| ||||
|
=-
7 |
15 |
已知tanx=2,则
|
∵tanx=2,
则
3sin2x+2cos2x |
cos2x-3sin2x |
6sinxcosx+2(cos2x-sin2x) |
cos2x-sin2x-6sinxcosx |
=
| ||||
|
=
| ||||
|
=-
7 |
15 |