问题
解答题
递等式计算:
(17-48÷24)×4
336÷[(36-29)×6]
62×(300-150÷25)
答案
(1)(17-48÷24)×4
=(17-2)×4
=15×4
=60;
(2)336÷[(36-29)×6]
=336÷[7×6]
=336÷42
=8;
(3)62×(300-150÷25)
=62×(300-6)
=62×300-62×6
=18600-372
=18228.
递等式计算:
(17-48÷24)×4
336÷[(36-29)×6]
62×(300-150÷25)
(1)(17-48÷24)×4
=(17-2)×4
=15×4
=60;
(2)336÷[(36-29)×6]
=336÷[7×6]
=336÷42
=8;
(3)62×(300-150÷25)
=62×(300-6)
=62×300-62×6
=18600-372
=18228.