问题 解答题
用递等式计算.
(1)2184-[(44×19+44)÷5](2)450+(8.16+6.84)÷0.63
(3)(
4
5
+
1
4
7
5
+
5
6
(4)[1-(
1
12
+
1
8
)×2]÷
1
12
(5)(4-7.5×
4
15
)÷
2
9
(6)
7
12
÷[(
1
4
+0.875)×
8
9
]-
1
4
答案

(1)2184-[(44×19+44)÷5],

=2184-[44×(19+1)÷5],

=2184-[44×20÷5],

=2184-[880÷5],

=2184-176,

=2008;

(2)450+(8.16+6.84)÷0.63,

=450+15÷0.63,

=450+23

17
21

=473

17
21

(3)(

4
5
+
1
4
7
5
+
5
6

=

21
20
÷
7
5
+
5
6

=

3
4
+
5
6

=

19
12

(4)[1-(

1
12
+
1
8
)×2]÷
1
12

=[1-

5
24
×2]÷
1
12

=[1-

5
12
1
12

=

7
12
÷
1
12

=7;

(5)(4-7.5×

4
15
)÷
2
9

=(4-2)÷

2
9

=2÷

2
9

=9;

(6)

7
12
÷[(
1
4
+0.875)×
8
9
]-
1
4

=

7
12
÷[1.125×
8
9
]-
1
4

=

7
12
÷1-
1
4

=

7
12
-
1
4

=

1
3

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