问题
解答题
计算: (1)
(2)
|
答案
(1)
•(22
-2
)+6
-3 3 1 2+ 3
=
×22
-2
×2
+6
-(2-3
)3
=4-2
+3
-2+3 3
=2;
(2)2 3
+6x27x3
-4x2x 3 3 x
=
×3x2 3
+6x•3x 1 3
-4x2•3x 1 x 3x
=2x
+2x3x
-4x3x 3x
=0.
计算: (1)
(2)
|
(1)
•(22
-2
)+6
-3 3 1 2+ 3
=
×22
-2
×2
+6
-(2-3
)3
=4-2
+3
-2+3 3
=2;
(2)2 3
+6x27x3
-4x2x 3 3 x
=
×3x2 3
+6x•3x 1 3
-4x2•3x 1 x 3x
=2x
+2x3x
-4x3x 3x
=0.