计算及解方程: (1)
(2)
(3)(x+3)2-25=0; (4)x2-3x+1=0. |
(1)原式=2
×3
-3
=6-4=2;16
(2)原式=8-
×2=8-1=7;1 2
(3)(x+3)2-25=0,
变形得:(x+3)2=25,
开方得:x+3=5或x+3=-5,
解得:x1=2,x2=-8;
(4)x2-3x+1=0,
这里a=1,b=-3,c=1,
∵△=9-4=5,
∴x=
,3± 5 2
则x1=
,x2=3+ 5 2
.3- 5 2
计算及解方程: (1)
(2)
(3)(x+3)2-25=0; (4)x2-3x+1=0. |
(1)原式=2
×3
-3
=6-4=2;16
(2)原式=8-
×2=8-1=7;1 2
(3)(x+3)2-25=0,
变形得:(x+3)2=25,
开方得:x+3=5或x+3=-5,
解得:x1=2,x2=-8;
(4)x2-3x+1=0,
这里a=1,b=-3,c=1,
∵△=9-4=5,
∴x=
,3± 5 2
则x1=
,x2=3+ 5 2
.3- 5 2