问题
解答题
计算 (1)
(2)(
(3)
|
答案
(1)原式=
×26 3 6
=2×6 3
=4;
(2)原式=(
)2-(27
)22
=7-8
=-1;
(3)原式=
+2(2
-10)15 5 5 5
=2
-23
+25 5
=2
.3
计算 (1)
(2)(
(3)
|
(1)原式=
×26 3 6
=2×6 3
=4;
(2)原式=(
)2-(27
)22
=7-8
=-1;
(3)原式=
+2(2
-10)15 5 5 5
=2
-23
+25 5
=2
.3