问题
解答题
用递等式计算. (1)[15.5-(1.5×
(2)[1
|
答案
(1)[15.5-(1.5×
+15 7
×1 2
)]÷14%2 7
=[
-(31 2
×3 2
+5 7
×3 2
)]÷2 7
,7 50
=[
-(31 2
+5 7
)×2 7
]×3 2
,50 7
=[
-31 2
]×3 2
,50 7
=14×
,50 7
=100;
(2)[1
+21 10
÷(37 20
-1.125)]×1 12
-9 23 1 6
=[
+11 10
÷(47 20
-37 12
)]×9 8
-9 23
,1 6
=[
+11 10
×47 20
]×24 47
-9 23
,1 6
=[
+11 10
]×12 10
-9 23
,1 6
=
×23 10
-9 23
,1 6
=
-9 10
,1 6
=
.11 15