计算,把结果写成若干个分母是质数的既约分数之和:
|
+1 9
-5 9
+1 19
-1 95 1 1995
=
-6 9
,105-21+1 1995
=
-2 3
,17 399
=
;83 133
133=7×19,
令
=83 133
+a 7
,b 19
则19×a+7×b=83,易见a=4,b=1,符合要求.
所以,
+1 9
-5 9
+1 19
-1 95
=1 1995
+4 7
.1 19
故答案为:
+4 7
.1 19
计算,把结果写成若干个分母是质数的既约分数之和:
|
+1 9
-5 9
+1 19
-1 95 1 1995
=
-6 9
,105-21+1 1995
=
-2 3
,17 399
=
;83 133
133=7×19,
令
=83 133
+a 7
,b 19
则19×a+7×b=83,易见a=4,b=1,符合要求.
所以,
+1 9
-5 9
+1 19
-1 95
=1 1995
+4 7
.1 19
故答案为:
+4 7
.1 19