问题 解答题

(0.12+0.23+0.34)×(0.23+0.34+0.45)-(0.12+0.23+0.34+0.45)×(0.23+0.34)=______.

答案

假设A=0.12+0.23+0.34,B=0.23+0.34

原式=A×(B+0.45)-(A+0.45)×B,

=AB+0.45A-AB-0.45B,

=0.45×(A-B);

把A=0.12+0.23+0.34,与B=0.23+0.34代入上式得:

0.45×(0.12+0.23+0.34-0.23-0.34),

=0.45×0.12,

=0.054.

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